题解 | #计算日期到天数转换#

#include<iostream>
using namespace std;
int main()
{
    static int array[13] = {0,31,28,31,30,31,30,31,31,30,31,30,31};
    int year,month,day;
    int ret = 0,flag = 0;
    while(cin>>year>>month>>day)
    {
        int i = 1;
        while(i < month)//计算第n-1月的天数
        {
            ret += array[i];
            i++;
        }
            ret += day;//计算第n月的天数
        if(month > 2 && ((year % 4 == 0 && year % 100 != 0 )|| year % 400 == 0))
        {

            ret += 1; //闰年的情况下加1天
        }
         cout<< ret <<endl;
    }



}