题解 | #输出单向链表中倒数第k个结点#
输出单向链表中倒数第k个结点
http://www.nowcoder.com/practice/54404a78aec1435a81150f15f899417d
import sys
while True:
try:
N = int(input())
L = list(map(int, input().split()))
I = int(input())
if I <= 0 or I > N:
print(0)#空指针输出0
else:
print(L[-I])
except:
# print(sys.exc_info())
break
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