题解 | #质数因子#

import sys
from math import sqrt

#判断是否质数
def is_prime(n):
    if n == 1:
        return False
    #n不可能存在两个比n开方大的质因子
    for i in range(2, int(sqrt(n) + 1)):
        if n % i == 0:
            return False
    return True

while True:
    try:
        d = int(input())
        if is_prime(d):
            print(d, end = " ")
        else:
            #把质数从小到大判断是否能整除
            i = 2
            while d > 1 and i < int(d / 2) + 1:
                if d % i != 0:
                    i += 1
                else:
                    print(i, end = " ")
                    d //= i
                    if is_prime(d):
                        print(d, end = " ")
                        break

#         print(get_zhi_shu())
    except:
#         print(sys.exc_info())
        break
















# import sys
# import math

# #判断是否质数
# def check_zhi_shu(num):
#     zhishu = True
#     l = int(math.sqrt(num)) + 1
#     for j in range(2, l):
#         if num % j == 0:
#             return False
#     return True

# # #获得质数
# # def get_zhi_shu():
# #     z = []
# #     for i in range(2, 1000):
# #         if check_zhi_shu(i):
# #             z.append(i)
# #     return z



# # z = [2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, 97, 101, 103, 107, 109, 113, 127, 131, 137, 139, 149, 151, 157, 163, 167, 173, 179, 181, 191, 193, 197, 199, 211, 223, 227, 229, 233, 239, 241, 251, 257, 263, 269, 271, 277, 281, 283, 293, 307, 311, 313, 317, 331, 337, 347, 349, 353, 359, 367, 373, 379, 383, 389, 397, 401, 409, 419, 421, 431, 433, 439, 443, 449, 457, 461, 463, 467, 479, 487, 491, 499, 503, 509, 521, 523, 541, 547, 557, 563, 569, 571, 577, 587, 593, 599, 601, 607, 613, 617, 619, 631, 641, 643, 647, 653, 659, 661, 673, 677, 683, 691, 701, 709, 719, 727, 733, 739, 743, 751, 757, 761, 769, 773, 787, 797, 809, 811, 821, 823, 827, 829, 839, 853, 857, 859, 863, 877, 881, 883, 887, 907, 911, 919, 929, 937, 941, 947, 953, 967, 971, 977, 983, 991, 997]
# # z = get_zhi_shu()
# while True:
#     try:
#         d = int(input())
#         if check_zhi_shu(d):
#             print(d, end = " ")
#         else:
#             #把质数从小到大判断是否能整除
#             i = 2
#             while d > 1 and i < int(d / 2) + 1:
#                 if d % i != 0:
#                     i += 1
#                 else:
#                     print(i, end = " ")
#                     d //= i
#                     if check_zhi_shu(d):
#                         print(d, end = " ")
#                         break

# #         print(get_zhi_shu())
#     except:
# #         print(sys.exc_info())
#         break