题解 | #拼凑面额#
树的子结构
http://www.nowcoder.com/practice/6e196c44c7004d15b1610b9afca8bd88
public class Solution {
public boolean HasSubtree(TreeNode root1,TreeNode root2) {
if(root2==null||root1==null)return false;
if(root1.val==root2.val){
if(isSubTree(root1,root2))return true;
}
return HasSubtree(root1.left,root2)||HasSubtree(root1.right,root2);
}
public boolean isSubTree(TreeNode root1,TreeNode root2){
if(root2==null)return true;
if(root1==null)return false;
if(root1.val!=root2.val)return false;
return isSubTree(root1.left,root2.left)&&isSubTree(root1.right,root2.right);
}
查看7道真题和解析
安克创新 Anker公司福利 607人发布