题解 | #最大最小值#

这里主要是用到了一个公式:
求最大值: return (a + b + abs(a-b))/2

#include <iostream>
#include <cmath>

using namespace std;

int max(int a,int b)
{
    return (a + b + abs(a-b))/2;
}

int min(int a,int b)
{
    int  x = (a + b + abs(a-b))/2;
    if(x == a) return b;
    else return a;
}

int main()
{
    int x,y,z;
    cin >> x >> y >> z;
    cout << "The maximum number is : "<< max(x,max(y,z)) << endl;
    cout << "The minimum number is : "<< min(x,min(y,z)) << endl;
    return 0;
}