题解 | #从单向链表中删除指定值的节点#
从单向链表中删除指定值的节点
http://www.nowcoder.com/questionTerminal/f96cd47e812842269058d483a11ced4f
思路：
👍最后的空格
代码：
while True:
try:
l = input().split()
head = l[1]
rm = l[-1]
l = l[2:-1]
res = [head]
for i in range(0, len(l), 2):
# i = i*2
# if i>len(l):
# break
a = l[i]
b = l[i+1]
res.insert(res.index(b)+1, a)
res.remove(rm)
print(' '.join(res)+" ")
except:
break
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