题解 | #鸡兔同笼#
鸡兔同笼
http://www.nowcoder.com/practice/fda725b4d9a14010bb145272cababef1
#include<iostream>
#include<cstdio>
using namespace std;
int main()
{
int a;
while(scanf("%d",&a) !=EOF){
int minimum=0;
int maxmum=0;
if (a%2==0){
minimum=a/4+(a%4)/2;
maxmum=a/2;
}
printf("%d %d\n",minimum,maxmum);
}
return 0;
}
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