题解 | #获取 url 参数#
获取 url 参数
http://www.nowcoder.com/practice/a3ded747e3884a3c86d09d88d1652e10
function getUrlParam(sUrl, sKey) {
let arr = sUrl.split("?")[1].split("#")[0].split("&");
const obj = {};
arr.forEach((item) => {
const subObj = item.split("=");
if (!Object.keys(obj).includes(subObj[0])) {
obj[subObj[0]] = subObj[1];
} else {
obj[subObj[0]] = [...obj[subObj[0]], ...subObj[1]];
}
});
return sKey===void 0 ? obj:obj[sKey]||''
