ACM模版
AC自动机
参考题目链接
HDU 2222 Keywords Search
代码
/*
* 求目标串中出现了几个模式串
*/
struct Trie
{
int next[500010][26], fail[500010], end[500010];
int root, L;
int newnode()
{
for (int i = 0; i < 26; i++)
{
next[L][i] = -1;
}
end[L++] = 0;
return L - 1;
}
void init()
{
L = 0;
root = newnode();
}
void insert(char buf[])
{
int len = (int)strlen(buf);
int now = root;
for (int i = 0; i < len; i++)
{
if (next[now][buf[i] -
{
next[now][buf[i] -
}
now = next[now][buf[i] -
}
end[now]++;
}
void build()
{
queue<int>Q;
fail[root] = root;
for (int i = 0; i < 26; i++)
{
if (next[root][i] == -1)
{
next[root][i] = root;
}
else
{
fail[next[root][i]] = root;
Q.push(next[root][i]);
}
}
while (!Q.empty())
{
int now = Q.front();
Q.pop();
for (int i = 0;i < 26;i++)
{
if (next[now][i] == -1)
{
next[now][i] = next[fail[now]][i];
}
else
{
fail[next[now][i]]=next[fail[now]][i];
Q.push(next[now][i]);
}
}
}
}
int query(char buf[])
{
int len = (int)strlen(buf);
int now = root;
int res = 0;
for (int i = 0; i < len; i++)
{
now = next[now][buf[i] -
int temp = now;
while (temp != root)
{
res += end[temp];
end[temp] = 0;
temp = fail[temp];
}
}
return res;
}
void debug()
{
for (int i = 0; i < L; i++)
{
printf("id = %3d,fail = %3d,end = %3d,chi = [", i, fail[i], end[i]);
for (int j = 0; j < 26; j++)
{
printf("%2d", next[i][j]);
}
printf("]\n");
}
}
};
char buf[1000010];
Trie ac;
int main()
{
int T;
int n;
scanf("%d", &T);
while(T--)
{
scanf("%d", &n);
ac.init();
for (int i = 0; i < n; i++)
{
scanf("%s", buf);
ac.insert(buf);
}
ac.build();
scanf("%s", buf);
printf("%d\n", ac.query(buf));
}
return 0;
}