题解 | #连分数#

看了其他大佬AC的代码，感觉和他们差距好远。
ACM赛制真的锻炼代码能力，之前刷题都是OI和IOI赛制，遇到ACM赛制没有反馈就有些慌^^

#include<iostream>
#include<string>
#include<memory.h>
using namespace std;

string s;
int m, n;

int main()
{
    int t;
    cin>>t;
    while (t--)
    {
        int cnt = 0;
        cin >> m >> n;
        s = to_string(m) + "/" + to_string(n);    //转换成字符串（可能没必要？）
        int a[1000], t = 0;
        memset(a, 0, sizeof(a));
        cout << m << "/" << n << " = ";
        if(m == n)    //特判相等的点(我原来错的点TnT)
        {
            cout << "1" <<endl;
            continue;
        }
        if(!m)
        {
            cout << "0" << endl;
            continue;
        }
        if(n % m == 0)    //注意如果是2/4 要输出0+1/2 不是1/2
        {
            cout << "0+1/" << n / m << endl;
            continue;
        }
        for (int i = 0; i < s.size(); i++)
        {
            if (s[i] >= '0' && s[i] <= '9')
            {
                a[t] = a[t] * 10 + (int)(s[i] - '0');
            }
            else
                t++;
        }
        if (t == 0)
            cout << a[0] << endl;
        else
        {
            int max = a[0], min = a[1];
            while (max % min != 0)
            {
                int temp = min;
                min = max % min;
                max = temp;
            }
            int x = a[0] / min, y = a[1] / min;
            t = 0;
            while (x != 1)
            {
                int div = x / y, rem = x % y;
                if (t == 0)
                    cout << div;
                else
                    cout << "+1/{" << div;
                cnt++;    //记录括号数
                x = rem;
                if (x != 1)
                    swap(x, y);
                t++;
            }
            if (y)
                cout << "+1/" << y;
            for (int i = cnt - 1; i > 0; i--)
                cout << '}';
            cout << endl;
        }
    }
    return 0;
}

整体思路就是把按位除了存放在数组里输出