题解 | #简单密码#
简单密码
http://www.nowcoder.com/practice/7960b5038a2142a18e27e4c733855dac
方法1:
code_str =input() dic ={"1":1,"abc":2,"def":3,"ghi":4,"jkl":5,"mno":6,"pqrs":7,"tuv":8,"wxyz":9,"0":0} out_str = [] for x in code_str: if x.islower(): # for key in dic: # dict.get(key, default=None)返回指定键的值,如果值不在字典中返回default值 # dict.items()以列表返回可遍历的(键, 值) 元组数组 for key,value in dic.items(): if x in key: out_str.append(str(value)) elif x.isupper(): if x.lower()=='z': x = 'a' else: x = chr(ord(x.lower())+1) out_str.append(x) elif x.isdigit(): out_str.append(x) out_str_join = ''.join(out_str) print(out_str_join)
方法2:
a = input() d = {"1":1,"abc":2,"def":3,"ghi":4,"jkl":5,"mno":6,"pqrs":7,"tuv":8,"wxyz":9,"0":0} L = '' for x in a: if x.islower(): for key,value in d.items(): if x in key: L = L + str(value) elif x.isupper(): if x.lower() != 'z': m = chr(ord(x.lower())+1) else: m = 'a' L = L + m else: L = L +x print(L)