题解 | #24点运算# 简洁版，一看就会

from itertools import permutations

card = ['A','2','3','4','5','6','7','8','9','10','J','Q','K']
order = range(1,14)
card_order = dict(zip(card,order))
opts = ["+", "-", "*", "/"]

def cal(a1,a2,opt):
    if opt == 0: return a1+a2
    elif opt == 1: return a1-a2
    elif opt == 2: return a1*a2
    elif opt == 3: return a1/a2

def cal24(cards):
    if "joker" in cards or "JOKER" in cards:
        print("ERROR")
        return
    num_orders = permutations(cards, 4)
    for nums in num_orders:
        for i in range(4):
            a = cal(card_order[nums[0]], card_order[nums[1]], i)
            for j in range(4):
                b = cal(a, card_order[nums[2]], j)
                for k in range(4):
                    c = cal(b, card_order[nums[3]], k)
                    if c == 24:
                        print("%s%s%s%s%s%s%s"%(nums[0],opts[i],nums[1],opts[j],nums[2],opts[k],nums[3]))
                        return
    print("NONE")
    return

cards = input().split()
cal24(cards)