python 解法
汽水瓶
http://www.nowcoder.com/questionTerminal/fe298c55694f4ed39e256170ff2c205f
python 解法
def drink_count(n):
if n < 2:
return 0
if n ==2:
return 1
else:
return n//3 + drink_count(n//3+n%3)
if '__name__' == '__main__':
while True:
try:
n = int(input())
if n == 0:
break
else:
print(drink_count(n))
except:
break
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