在二叉树中找两个节点的最近公共祖先
在二叉树中找到两个节点的最近公共祖先
https://www.nowcoder.com/practice/e0cc33a83afe4530bcec46eba3325116?tpId=196&tags=&title=&diffculty=0&judgeStatus=0&rp=0&tab=answerKey
public int lowestCommonAncestor (TreeNode root, int o1, int o2) { // write code here TreeNode res = dfs(root,o1,o2); if (res==null) return -1; return res.val; } private TreeNode dfs(TreeNode root, int o1, int o2) { if (root==null) return null; if (root.val==o1 || root.val==o2) return root; TreeNode left = dfs(root.left,o1,o2); TreeNode right = dfs(root.right,o1,o2); if (left!=null && right!=null) return root; if (left==null) return right; return left; }