正常层序遍历后翻转输出
二叉树的之字形层序遍历
http://www.nowcoder.com/questionTerminal/47e1687126fa461e8a3aff8632aa5559
/**
* struct TreeNode {
* int val;
* struct TreeNode *left;
* struct TreeNode *right;
* };
*/
class Solution {
public:
/**
*
* @param root TreeNode类
* @return int整型vector<vector<>>
*/
vector<vector<int> > zigzagLevelOrder(TreeNode* root) {
// write code here
if (!root)
return {};
vector<vector<int> > ret;
queue<TreeNode*> q;
q.push(root);
vector<int> tmp;
while (!q.empty()) {
tmp.clear();
int currentSize = q.size();
for (int i = 0; i < currentSize; i++) {
TreeNode *node = q.front();
q.pop();
tmp.push_back(node->val);
if (node->left)
q.push(node->left);
if (node->right)
q.push(node->right);
}
ret.push_back(tmp);
} //层序遍历
//翻转Z型
for (int i = 0; i < ret.size(); i++)
if (i & 1 != 0)
reverse(ret[i].begin(), ret[i].end());
return ret;
}
};
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