python

'''
思路：
根据输入构建二位数组A、B来代表两个矩阵
[x*y] * [y:z] =  [x*z————用res构建一个x行z列的矩阵[[0 for x in range(z)] for x in range(x)
计算矩阵，遍历行x、遍历列z，遍历元素下标y
根据矩阵计算方法，第i行第j列的结果就是res[i][j] += A[i][k]*B[k][j] 累加计算对应位置的值
打印输出res
'''
while True:
    try:
        x = int(input())
        y = int(input())
        z = int(input())
        A,B = [],[]
        res = [[0 for x in range(z)] for x in range(x)]
        for i in range(x):
            A += [list(map(int,input().split()))]
        for i in range(y):
            B += [list(map(int,input().split()))]
        for i in range(x):
            for j in range(z):
                for k in range(y):
                    res[i][j] += A[i][k]*B[k][j] 
        for x in res:
            print(*x)
    except:
        break