Euclid's Game（辗转相除博弈）

Two players, Stan and Ollie, play, starting with two natural numbers. Stan, the first player, subtracts any positive multiple of the lesser of the two numbers from the greater of the two numbers, provided that the resulting number must be nonnegative. Then Ollie, the second player, does the same with the two resulting numbers, then Stan, etc., alternately, until one player is able to subtract a multiple of the lesser number from the greater to reach 0, and thereby wins. For example, the players may start with (25,7):

25 7

11 7

4 7

4 3

1 3

1 0

an Stan wins.

Input
The input consists of a number of lines. Each line contains two positive integers giving the starting two numbers of the game. Stan always starts.

Output
For each line of input, output one line saying either Stan wins or Ollie wins assuming that both of them play perfectly. The last line of input contains two zeroes and should not be processed.

Sample Input
34 12
15 24
0 0

Sample Output
Stan wins
Ollie wins

大数除以小数，如果结果大于1，则正在进行游戏的玩家赢，否则继续游戏，最终进行游戏的次数为偶数则Ollie赢，奇数Stan赢

#include <bits/stdc++.h>
using namespace std;
int main()
{
   
    int t,n,i,m,a;
    while(scanf("%d%d",&m,&n)!=EOF&&m&&n)
    {
   
        t=0;
        while(m&&n)
        {
   
            t++;
            if(m>=n)
            {
   
                a=m/n;
                m%=n;
                if(a>1)
                    break;
            }
            else
            {
   
                a=n/m;
                n%=m;
                if(a>1)
                    break;
            }
        }
        if(t%2)
            cout<<"Stan wins"<<'\n';
        else
            cout<<"Ollie wins"<<'\n';
    }
    return 0;
}