【题解】跳跃
跳跃
https://ac.nowcoder.com/acm/problem/25160
广搜,搜到4以后广搜的层数就是答案。
#include<iostream> #include<queue> using namespace std; const int MAXN = 50; int G[MAXN][MAXN]; bool visit[MAXN][MAXN]; struct node{ int x,y,cur; }; int main() { int M,N,M1,M2; cin >> M >> N >> M1 >> M2; int sx,sy,ex,ey; for(int i = 1 ;i <= M ; i++) { for(int j = 1 ; j <= N ; j++) { cin >> G[i][j]; if(G[i][j]==3){sx = i;sy = j;} if(G[i][j]==4){ex = i;ey = j;} } } int dir[8][2]={{M1,M2},{-M1,M2},{M1,-M2},{-M1,-M2}, {M2,M1},{-M2,M1},{M2,-M1},{-M2,-M1}}; queue<node> Q; Q.push(node{sx,sy,0}); visit[sx][sy]=true; int ans = 0; while(!Q.empty()) { node now = Q.front(); int x = now.x; int y = now.y; int cur = now.cur; if(x==ex&&y==ey) { ans = cur; break; } Q.pop(); for(int i = 0 ; i < 8 ; i++) { int tx = x+dir[i][0]; int ty = y+dir[i][1]; if(!(tx>=1&&tx<=M)&&!(ty>=1&&ty<=N)) { continue; } if((!visit[tx][ty])&&(G[tx][ty]==1||G[tx][ty]==4)) { visit[tx][ty]=true; Q.push(node{tx,ty,cur+1}); } } } cout<<ans<<endl; return 0; }