2020牛客暑期多校训练营（第二场）D

题目描述

Given two moments on the same day in the form of HH:MM:SS, print the number of seconds between the two moments.

输入描述

Input two lines each contains a string in the form of , denoting a given moment.

输出描述

Only one line containing one integer, denoting the answer.

示例1

输入

12:00:00
17:00:00

输出

18000

示例2

输入

23:59:59
00:00:00

输出

86399

分析

  以每天的 作为基准，分别算出两个时刻距离基准的时间间隔 ，两个时间间隔差的绝对值即为答案。

代码

/******************************************************************
Copyright: 11D_Beyonder All Rights Reserved
Author: 11D_Beyonder
Problem ID: 2020牛客暑期多校训练营（第二场） Problem D
Date: 8/11/2020
Description: Easy Calculation
*******************************************************************/
#include<iostream>
#include<cmath>
#include<cstdio>
using namespace std;
int main()
{
    int HH,MM,SS;
    scanf("%d:%d:%d",&HH,&MM,&SS);
    int a=HH*3600+MM*60+SS;
    scanf("%d:%d:%d",&HH,&MM,&SS);
    int b=HH*3600+MM*60+SS;
    cout<<abs(a-b)<<endl;
    return 0;
}