直接循环累乘
数值的整数次方
http://www.nowcoder.com/questionTerminal/1a834e5e3e1a4b7ba251417554e07c00
思路就是暴力累乘：
public class Solution {
public double Power(double base, int exponent) {
if (base == 0.0) {
return base;
}
double sum = 1.0d;
int n = exponent > 0 ? exponent : -exponent;
while (n > 0) {
sum = sum * base;
n = n - 1;
}
return exponent > 0 ? sum : 1 / sum;
}
}
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