python 双指针
链表中环的入口结点
http://www.nowcoder.com/questionTerminal/253d2c59ec3e4bc68da16833f79a38e4
class Solution:
def EntryNodeOfLoop(self, pHead): # write code here if not pHead or not pHead.next: return slow = pHead fast = pHead while fast.next.next: slow = slow.next fast = fast.next.next if slow == fast: break slow = pHead while slow != fast: slow = slow.next fast = fast.next return slow