NC15163 逆序数 归并
给定一个数组,求逆序对个数
- 逆序对个数等于冒泡排序的交换次数
- 归并排序的过程中可以统计出答案
- 不开 long long凉凉
void merge_sort(int lef, int rig) {
if(lef == rig) return ;
int mid = (lef + rig) >> 1;
merge_sort(lef, mid);
merge_sort(mid+1, rig);
int x = lef, y = mid + 1, i = 0;
for( ; i<(rig-lef+1); i++) {
if(x<=mid && y<=rig) { //发生逆序
if(a[x] > a[y]) {
ans += mid - x + 1; //统计答案
tmp[i] = a[y++];
} else
tmp[i] = a[x++];
} else {
if(x <= mid) tmp[i] = a[x++];
if(y <= rig) tmp[i] = a[y++];
}
}
while(~(--i)) a[rig--] = tmp[i];
}
完整代码
#define debug
#ifdef debug
#include <time.h>
#include "/home/majiao/mb.h"
#endif
#include <iostream>
#include <algorithm>
#include <vector>
#include <string.h>
#include <map>
#include <set>
#include <stack>
#include <queue>
#include <math.h>
#define MAXN ((int)1e5+7)
#define ll long long int
#define INF (0x7f7f7f7f)
#define fori(lef, rig) for(int i=lef; i<=rig; i++)
#define forj(lef, rig) for(int j=lef; j<=rig; j++)
#define fork(lef, rig) for(int k=lef; k<=rig; k++)
#define QAQ (0)
using namespace std;
#ifdef debug
#define show(x...) \ do { \ cout << "\033[31;1m " << #x << " -> "; \ err(x); \ } while (0)
void err() { cout << "\033[39;0m" << endl; }
template<typename T, typename... A>
void err(T a, A... x) { cout << a << ' '; err(x...); }
#endif
#ifndef debug
namespace FIO {
template <typename T>
void read(T& x) {
int f = 1; x = 0;
char ch = getchar();
while (ch < '0' || ch > '9')
{ if (ch == '-') f = -1; ch = getchar(); }
while (ch >= '0' && ch <= '9')
{ x = x * 10 + ch - '0'; ch = getchar(); }
x *= f;
}
};
using namespace FIO;
#endif
int n, m, Q, K, a[MAXN], tmp[MAXN];
ll ans;
void merge_sort(int lef, int rig) {
// forarr(a, lef, rig);
if(lef == rig) return ;
int mid = (lef + rig) >> 1;
merge_sort(lef, mid);
merge_sort(mid+1, rig);
int x = lef, y = mid + 1, i = 0;
for( ; i<(rig-lef+1); i++) {
if(x<=mid && y<=rig) {
if(a[x] > a[y]) {
ans += mid - x + 1;
tmp[i] = a[y++];
} else
tmp[i] = a[x++];
} else {
if(x <= mid) tmp[i] = a[x++];
if(y <= rig) tmp[i] = a[y++];
}
}
while(~(--i)) a[rig--] = tmp[i];
}
int main() {
#ifdef debug
freopen("test", "r", stdin);
clock_t stime = clock();
#endif
read(n);
for(int i=1; i<=n; i++) read(a[i]);
merge_sort(1, n);
// forarr(a, 1, n);
// show(ans);
printf("%lld\n", ans);
#ifdef debug
clock_t etime = clock();
printf("rum time: %lf 秒\n",(double) (etime-stime)/CLOCKS_PER_SEC);
#endif
return 0;
}