C 语言-简单计算器

简单计算器

http://www.nowcoder.com/questionTerminal/b8f770674ba7468bb0a0efcc2aa3a239

#include<stdio.h>
int main()
{
    double a,b;//最初用float,通过率90%
    char o;
    while(scanf("%lf%c%lf",&a,&o,&b)!=EOF)
    {
        switch(o)
        {
            case '+':printf("%.4f+%.4f=%.4f\n",a,b,a+b);break;
            case '-':printf("%.4f-%.4f=%.4f\n",a,b,a-b);break;
            case '*':printf("%.4f*%.4f=%.4f\n",a,b,a*b);break;
            case '/':
            if(b==0)
            {
                printf("Wrong!Division by zero!\n");
            }
            else
            {
                printf("%.4f/%.4f=%.4f\n",a,b,a/b);
            }
            break;
            default:printf("Invalid operation!\n");break;
        }
    }
    return 0;
}

参考资料:https://www.runoob.com/cprogramming/c-examples-calculator-switch-case.html

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