python中序遍历
二叉搜索树的第k个结点
http://www.nowcoder.com/questionTerminal/ef068f602dde4d28aab2b210e859150a
class Solution:
# 返回对应节点TreeNode
def KthNode(self, pRoot, k): # write code here self.k = k self.res = None def helper(node): if not node: return if node.left: helper(node.left) if self.k == 1: self.res = node self.k -= 1 if node.right: helper(node.right) helper(pRoot) return self.res