实现LFU缓存置换算法(Python)
关于LFU
最不经常使用算法,淘汰缓存时,把使用频率最小的淘汰掉,当多个节点使用频率相同时,按照FIFO算法淘汰。
具体实现(Python)
(代码中引进的双向链表内容请查看-->https://blog.csdn.net/huanglei305/article/details/99422314)
# -*- encoding=utf-8 -*-
from computer_principle.DoubleLinkedList import DoubleLinkedList, Node
class LFUNode(Node):
def __init__(self, key, value):
self.freq = 0
super(LFUNode, self).__init__(key, value)
class LFUCache(object):
def __init__(self, capacity):
self.capacity = capacity
self.map = {}
# key: 频率, value: 频率对应的双向链表
self.freq_map = {}
self.size = 0
# 更新节点频率的操作
def __update_freq(self, node):
freq = node.freq
# 删除
node = self.freq_map[freq].remove(node)
if self.freq_map[freq].size == 0:
del self.freq_map[freq]
# 更新
freq += 1
node.freq = freq
if freq not in self.freq_map:
self.freq_map[freq] = DoubleLinkedList()
self.freq_map[freq].append(node)
def get(self, key):
if key not in self.map:
return -1
node = self.map.get(key)
self.__update_freq(node)
return node.value
def put(self, key, value):
if self.capacity == 0:
return
# 缓存命中
if key in self.map:
node = self.map.get(key)
node.value = value
self.__update_freq(node)
# 缓存没有命中
else:
if self.capacity == self.si***_freq = min(self.freq_map)
node = self.freq_map[min_freq].pop()
del self.map[node.key]
self.size -= 1
node = LFUNode(key, value)
node.freq = 1
self.map[key] = node
if node.freq not in self.freq_map:
self.freq_map[node.freq] = DoubleLinkedList()
node = self.freq_map[node.freq].append(node)
self.size += 1
def print(self):
print('***************************')
for k, v in self.freq_map.items():
print('Freq = %d' % k)
self.freq_map[k].print()
print('***************************')
print()
if __name__ == '__main__':
cache = LFUCache(2)
cache.put(1, 1)
cache.print()
cache.put(2, 2)
cache.print()
print(cache.get(1))
cache.print()
cache.put(3, 3)
cache.print()
print(cache.get(2))
cache.print()
print(cache.get(3))
cache.print()
cache.put(4, 4)
cache.print()
print(cache.get(1))
cache.print()
print(cache.get(3))
cache.print()
print(cache.get(4))
cache.print()
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