不用正则的方式

python代码，逻辑清晰
判断字符串是否为空，第一个字母是否为wasd，后面的字符串（运用集合的子集）是否为数字即可

while True:
    try:
        val = input()
        tmp = val.split(";")
        x,y = 0,0
        comp = set("1234567890")
        for i in tmp:
            if not i or i[0] not in ["A","D","W","S"] or set(i[1:]).issubset(set("1234567890")) == False:
                continue
            elif i[0] == "A":
                x -= int(i[1:])
            elif i[0] == "S":
                y -= int(i[1:])
            elif i[0] == "W":
                y += int(i[1:])
            elif i[0] == "D":
                x += int(i[1:])
        print(str(x)+","+str(y)) 
    except:
        break