题解
在链表中删除指定值的节点
http://www.nowcoder.com/questionTerminal/1a5fd679e31f4145a10d46bb8fd3d211
list_node * remove_value(list_node * head, int num)
{
//////在下面完成代码
while(head->val == num) head = head->next;
list_node* cur = head;
while(cur->next != nullptr) {
if(cur->next->val == num) {
cur->next = cur->next->next;
} else cur = cur->next;
}
return head;
}
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