简单密码 python3的粗暴解法
简单密码
http://www.nowcoder.com/questionTerminal/7960b5038a2142a18e27e4c733855dac
while True: try: s = input() res = [] for i in s: if i.isdigit(): res.append(i) elif i.isupper() and i != 'Z': res.append(chr(ord(i.lower()) + 1)) elif i == 'Z': res.append('a') else: if i in 'abc': res.append('2') elif i in 'def': res.append('3') elif i in 'ghi': res.append('4') elif i in 'jkl': res.append('5') elif i in 'mno': res.append('6') elif i in 'pqrs': res.append('7') elif i in 'tuv': res.append('8') else: res.append('9') print(''.join(res)) except: break简单粗暴没什么好讲的