LeetCode 232. 用栈实现队列
原题链接:
https://leetcode.com/problems/implement-queue-using-stacks/description/
https://leetcode-cn.com/problems/implement-queue-using-stacks/description/
这道题其实比较简单,题目要求就是用栈实现一个队列。
我们考虑有两个栈,一个输入栈,一个输出栈。
放数据永远放入输入栈,取数据永远从输出栈取。
输出栈为空的时候把把输入栈的数据一次性取出来放到输出栈。
下面是 Java 和 Python 的代码
Java
class MyQueue {
private Stack<Integer> input = null;
private Stack<Integer> output = null;
/** Initialize your data structure here. */
public MyQueue() {
input = new Stack<>();
output = new Stack<>();
}
/** Push element x to the back of queue. */
public void push(int x) {
input.push(x);
}
/** Removes the element from in front of queue and returns that element. */
public int pop() {
if(output.isEmpty()) {
while(!input.isEmpty()) {
output.push(input.pop());
}
}
return output.pop();
}
/** Get the front element. */
public int peek() {
if(output.isEmpty()) {
while(!input.isEmpty()) {
output.push(input.pop());
}
}
return output.peek();
}
/** Returns whether the queue is empty. */
public boolean empty() {
return input.isEmpty() && output.isEmpty();
}
}
Python
class MyQueue:
def __init__(self):
""" Initialize your data structure here. """
self.instack = []
self.outstack = []
def push(self, x):
""" Push element x to the back of queue. :type x: int :rtype: void """
self.instack.append(x)
def pop(self):
""" Removes the element from in front of queue and returns that element. :rtype: int """
if not self.outstack:
while self.instack:
self.outstack.append(self.instack.pop())
return self.outstack.pop()
def peek(self):
""" Get the front element. :rtype: int """
if not self.outstack:
while self.instack:
self.outstack.append(self.instack.pop())
return self.outstack[-1]
def empty(self):
""" Returns whether the queue is empty. :rtype: bool """
return not self.outstack and not self.instack