HDU 1000 & HDU1001 & 字符串连接
A + B Problem
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 571020 Accepted Submission(s): 181151
Problem Description
Calculate A + B.
Input
Each line will contain two integers A and B. Process to end of file.
Output
For each case, output A + B in one line.
Sample Input
1 1
Sample Output
2
#include <iostream> #include <cstdio> using namespace std; int main() { int a=1,b=1; while(scanf("%d %d",&a,&b)!=EOF){ printf("%d\n",a+b); } return 0; }
Sum Problem
Time Limit: 1000/500 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 410639 Accepted Submission(s): 103262
Problem Description
Hey, welcome to HDOJ(Hangzhou Dianzi University Online Judge).
In this problem, your task is to calculate SUM(n) = 1 + 2 + 3 + ... + n.
In this problem, your task is to calculate SUM(n) = 1 + 2 + 3 + ... + n.
Input
The input will consist of a series of integers n, one integer per line.
Output
For each case, output SUM(n) in one line, followed by a blank line. You may assume the result will be in the range of 32-bit signed integer.
Sample Input
1 100
Sample Output
1 5050
#include <iostream> #include <cstdio> using namespace std; int main() { int t; int sum=0; while(scanf("%d",&t)!=EOF){ for(int i=1;i<=t;i++){ sum+=i; } printf("%d\n\n",sum); sum=0; } return 0; }
字符串连接：
#include <iostream> #include <cstdio> using namespace std; int main() { char a[20]="i love"; char b[20]="you!"; char c[40]; sprintf(c,"%s %s",a,b); printf("%s",c); return 0; }
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