HDU 2602 Bone Collector
Problem Description
Many years ago , in Teddy’s hometown there was a man who was called “Bone Collector”. This man like to collect varies of bones , such as dog’s , cow’s , also he went to the grave …
The bone collector had a big bag with a volume of V ,and along his trip of collecting there are a lot of bones , obviously , different bone has different value and different volume, now given the each bone’s value along his trip , can you calculate out the maximum of the total value the bone collector can get ?
Input
The first line contain a integer T , the number of cases.
Followed by T cases , each case three lines , the first line contain two integer N , V, (N <= 1000 , V <= 1000 )representing the number of bones and the volume of his bag. And the second line contain N integers representing the value of each bone. The third line contain N integers representing the volume of each bone.
Output
One integer per line representing the maximum of the total value (this number will be less than 231).
Sample Input
1
5 10
1 2 3 4 5
5 4 3 2 1
Sample Output
14
题目大意：
输入一个数a，表示有a组测试数据，输入b和c分别表示骨头重量和背包容量，数组m存骨头价值，数组w存骨头重量，求最大价值。
C++
#include<iostream>
#include<cstring>
#include<cmath>
using namespace std;
int main()
{
int m[1005],n[1005],w[1005];
int a,b,c,d,e,f;
cin>>a;
while(a--)
{
cin>>b>>c;
for(int i=0;i<b;i++)
cin>>m[i];
for(int i=0;i<b;i++)
cin>>w[i];
memset(n,0,sizeof(n));
for(int i=0;i<b;i++)
{
for(d=c;d>=w[i];d--)
{
n[d]=max(n[d],n[d-w[i]]+m[i]);
}
}
cout<<n[c]<<endl;
}
return 0;
}
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