luoguP2173 [ZJOI2012]网络 LCT
链接
思路
颜色很少,开10个lct分别维护
if (Hash.count(make_pair(u, v)) && Hash[make_pair(u, v)] == col) {puts("Success.");continue;}
这一行的代码调了半天。
代码
#include <bits/stdc++.h>
#define ls c[x][0]
#define rs c[x][1]
using namespace std;
const int N = 5e4 + 7;
int read() {
int x = 0, f = 1; char s = getchar();
for (;s > '9' || s < '0'; s = getchar()) if (s == '-') f = -1;
for (;s >= '0' && s <= '9'; s = getchar()) x = x * 10 + s - '0';
return x * f;
}
map<pair<int, int>, int> Hash;
int n, m, c, k, w[N];
struct LCT {
int ru[N];
int f[N], c[N][2], ma[N], stak[N], lazy[N];
bool isroot(int x) {return c[f[x]][0] == x || c[f[x]][1] == x;}
void pushup(int x) {ma[x] = max(max(ma[ls], ma[rs]), w[x]);}
void tag(int x){swap(ls,rs), lazy[x] ^= 1;}
void pushdown(int x) {
if (lazy[x]) {
if (ls) tag(ls);
if (rs) tag(rs);
lazy[x] ^= 1;
}
}
void rotate(int x) {
int y = f[x], z = f[y], k = c[y][1] == x, w = c[x][!k];
if (isroot(y)) c[z][c[z][1] == y] = x;
c[x][!k] = y;
c[y][k] = w;
if (w) f[w] = y;
f[x] = z;
f[y] = x;
pushup(y);
}
void splay(int x) {
int y = x, z = 0;
stak[++z] = y;
while (isroot(y)) stak[++z] = y = f[y];
while (z) pushdown(stak[z--]);
while (isroot(x)) {
y = f[x], z = f[y];
if (isroot(y)) rotate((c[y][0] == x)^(c[z][0] == y) ? x : y);
rotate(x);
}
pushup(x);
}
void access(int x) {
for (int y = 0; x;x = f[y = x])
splay(x), rs = y, pushup(x);
}
void makeroot(int x) {
access(x), splay(x);
tag(x);
}
int findroot(int x) {
access(x), splay(x);
while(ls) pushdown(x), x = ls;
return x;
}
void split(int x, int y) {
makeroot(x), access(y), splay(y);
}
void link(int x, int y) {
makeroot(x);
if (findroot(y) != x) f[x] = y;
}
void cut(int x, int y) {
makeroot(x);
if (findroot(y) == x && f[x] == y && !rs) {
f[x] = c[y][0] = 0;
pushup(y);
}
}
}lct[11];
int main() {
// freopen("a.in", "r", stdin);
int n = read(), m = read(), c = read(), k = read();
for (int i = 1; i <= n; ++i) w[i] = read();
for (int i = 1; i <= m; ++i) {
int u = read(), v = read(), col = read();
Hash[make_pair(u, v)] = col;
Hash[make_pair(v, u)] = col;
lct[col].link(u, v);
lct[col].ru[u]++,lct[col].ru[v]++;
}
for (int i = 1; i <= k; ++i) {
int opt = read();
if (opt == 0) {
int x = read(), y = read();
w[x] = y;
for (int j = 0; j <= c; ++j)
lct[j].splay(x),lct[j].pushup(x);
} else if (opt == 1) {
int u = read(), v = read(), col = read();
if (Hash.count(make_pair(u, v)) && Hash[make_pair(u, v)] == col) {puts("Success.");continue;}
if (!Hash.count(make_pair(u, v))) {puts("No such edge.");continue;}
if (lct[col].ru[u] >= 2 || lct[col].ru[v] >= 2) {puts("Error 1.");continue;}
if (lct[col].findroot(u) == lct[col].findroot(v)) {puts("Error 2.");continue;}
int old_col = Hash[make_pair(u,v)];
Hash[make_pair(u, v)] = Hash[make_pair(v, u)] = col;
lct[old_col].ru[u]--, lct[old_col].ru[v]--;
lct[col].ru[u]++, lct[col].ru[v]++;
lct[old_col].cut(u, v);
lct[col].link(u, v);
puts("Success.");
} else {
int col = read(), u = read(), v = read();
if (lct[col].findroot(u) == lct[col].findroot(v)) {
lct[col].split(u, v);
printf("%d\n", lct[col].ma[v]);
} else puts("-1");
}
}
return 0;
}