CREATE TABLE IF NOT EXISTS titles_test ( id int(11) not null primary key, emp_no int(11) NOT NULL, title varchar(50) NOT NULL, from_date date NOT NULL, to_date date DEFAULT NULL ); insert into titles_test values ('1', '10001', 'Senior Engineer', '1986-06-26', '9999-01-01'), ('2', '10002', 'Staff', '1996-08-03', '9999-01-01'), ('3', '10003', 'Senior Engineer', '1995-12-03', '9999-01-01'), ('4', '10004', 'Senior Engineer', '1995-12-03', '9999-01-01'), ('5', '10001', 'Senior Engineer', '1986-06-26', '9999-01-01'), ('6', '10002', 'Staff', '1996-08-03', '9999-01-01'), ('7', '10003', 'Senior Engineer', '1995-12-03', '9999-01-01');
更新后的值:
titles_test 表的值:
id | emp_no | title | from_date | to_date |
1 | 10001 | Senior Engineer | 2001-01-01 | NULL |
2 | 10002 | Staff | 2001-01-01 | NULL |
3 | 10003 | Senior Engineer | 2001-01-01 | NULL |
4 | 10004 | Senior Engineer | 2001-01-01 | NULL |
5 | 10001 | Senior Engineer | 2001-01-01 | NULL |
6 | 10002 | Staff | 2001-01-01 | NULL |
7 | 10003 | Senior Engineer | 2001-01-01 | NULL |
后台会执行下面SQL语句得到输出,判断正确:
select count(*) from titles_test where from_date='2001-01-01' and to_date is NULL;