有一个员工表employees简况如下: emp_no birth_date first_name last_name gender hire_date 10001 1953-09-02 Georgi Facello M 1986-06-26 10002 1964-06-02 Bezalel Simmel F 1985-11-21 10003 1959-12-03 Parto Bamford M 1986-08-28 10004 1954-05-01 Chirstian Koblick M 1986-12-01 有一个薪水表salaries简况如下: emp_no salary from_date to_date 10001 88958 2002-06-26 9999-01-01 10002 72527 2001-08-02 9999-01-01 10003 43311 2001-12-01 9999-01-01 10004 74057 2001-11-27 9999-01-01 请你查找薪水排名第二多的员工编号emp_no、薪水salary、last_name以及first_name，不能使用order by完成，以上例子输出为: （温馨提示:sqlite通过的代码不一定能通过mysql，因为SQL语法规定，使用聚合函数时，select子句中一般只能存在以下三种元素：常数、聚合函数，group by 指定的列名。如果使用非group by的列名，sqlite的结果和mysql 可能不一样) emp_no salary last_name first_name 10004 74057 Koblick Chirstian
示例1

输入

drop table if exists  `employees` ; 
drop table if exists  `salaries` ; 
CREATE TABLE `employees` (
`emp_no` int(11) NOT NULL,
`birth_date` date NOT NULL,
`first_name` varchar(14) NOT NULL,
`last_name` varchar(16) NOT NULL,
`gender` char(1) NOT NULL,
`hire_date` date NOT NULL,
PRIMARY KEY (`emp_no`));
CREATE TABLE `salaries` (
`emp_no` int(11) NOT NULL,
`salary` int(11) NOT NULL,
`from_date` date NOT NULL,
`to_date` date NOT NULL,
PRIMARY KEY (`emp_no`,`from_date`));
INSERT INTO employees VALUES(10001,'1953-09-02','Georgi','Facello','M','1986-06-26');
INSERT INTO employees VALUES(10002,'1964-06-02','Bezalel','Simmel','F','1985-11-21');
INSERT INTO employees VALUES(10003,'1959-12-03','Parto','Bamford','M','1986-08-28');
INSERT INTO employees VALUES(10004,'1954-05-01','Chirstian','Koblick','M','1986-12-01');
INSERT INTO salaries VALUES(10001,88958,'2002-06-22','9999-01-01');
INSERT INTO salaries VALUES(10002,72527,'2001-08-02','9999-01-01');
INSERT INTO salaries VALUES(10003,43311,'2001-12-01','9999-01-01');
INSERT INTO salaries VALUES(10004,74057,'2001-11-27','9999-01-01');

输出

10004|74057|Koblick|Chirstian
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