有一个员工表employees简况如下: emp_no birth_date first_name last_name gender hire_date 10001 1953-09-02 Georgi Facello M 1986-06-26 10002 1964-06-02 Bezalel Simmel F 1996-08-03 有一个，部门员工关系表dept_emp简况如下: emp_no dept_no from_date to_date 10001 d001 1986-06-26 9999-01-01 10002 d001 1996-08-03 9999-01-01 有一个部门经理表dept_manager简况如下: dept_no emp_no from_date to_date d001 10002 1996-08-03 9999-01-01 有一个薪水表salaries简况如下: emp_no salary from_date to_date 10001 88958 1986-06-26 9999-01-01 10002 72527 1996-08-03 9999-01-01 获取所有非manager员工薪水情况，给出dept_no、emp_no以及salary，以上例子输出: dept_no emp_no salary d001 10001 88958
示例1

输入

drop table if exists  `dept_emp` ; 
drop table if exists  `dept_manager` ; 
drop table if exists  `employees` ; 
drop table if exists  `salaries` ; 
CREATE TABLE `dept_emp` (
`emp_no` int(11) NOT NULL,
`dept_no` char(4) NOT NULL,
`from_date` date NOT NULL,
`to_date` date NOT NULL,
PRIMARY KEY (`emp_no`,`dept_no`));
CREATE TABLE `dept_manager` (
`dept_no` char(4) NOT NULL,
`emp_no` int(11) NOT NULL,
`from_date` date NOT NULL,
`to_date` date NOT NULL,
PRIMARY KEY (`emp_no`,`dept_no`));
CREATE TABLE `employees` (
`emp_no` int(11) NOT NULL,
`birth_date` date NOT NULL,
`first_name` varchar(14) NOT NULL,
`last_name` varchar(16) NOT NULL,
`gender` char(1) NOT NULL,
`hire_date` date NOT NULL,
PRIMARY KEY (`emp_no`));
CREATE TABLE `salaries` (
`emp_no` int(11) NOT NULL,
`salary` int(11) NOT NULL,
`from_date` date NOT NULL,
`to_date` date NOT NULL,
PRIMARY KEY (`emp_no`,`from_date`));
INSERT INTO dept_emp VALUES(10001,'d001','1986-06-26','9999-01-01');
INSERT INTO dept_emp VALUES(10002,'d001','1996-08-03','9999-01-01');
INSERT INTO dept_manager VALUES('d001',10002,'1996-08-03','9999-01-01');
INSERT INTO employees VALUES(10001,'1953-09-02','Georgi','Facello','M','1986-06-26');
INSERT INTO employees VALUES(10002,'1964-06-02','Bezalel','Simmel','F','1996-08-03');
INSERT INTO salaries VALUES(10001,88958,'1986-06-26','9999-01-01');
INSERT INTO salaries VALUES(10002,72527,'1996-08-03','9999-01-01');

输出

d001|10001|88958
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